\int_{-\infty}^{\infty} e^{-x^2} dx = \sqrt{\pi}
f(x) = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}
\lim_{n \to \infty} (1 + \frac{1}{n})^n = e
\sum_{i=1}^{n} i = \frac{n(n+1)}{2}
e^{i\pi} + 1 = 0
\frac{d}{dx}[\ln(x)] = \frac{1}{x}
\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t}
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Last Updated: June 30, 2026
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